2x^2+20x=150

Solution for 2x^2+20x=150 equation:

2x^2+20x=150

We move all terms to the left:

2x^2+20x-(150)=0

a = 2; b = 20; c = -150;
Δ = b2-4ac
Δ = 202-4·2·(-150)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*2}=\frac{-60}{4}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*2}=\frac{20}{4}
=5
$